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ï k x p i x § s h g n n k u p g § q x i s j iProof lnexy = xy = lnex lney = ln(ex ·ey) Since lnx is onetoone, then exy = ex ·ey 1 = e0 = ex(−x) = ex ·e−x ⇒ e−x = 1 ex ex−y = ex(−y) = ex ·e−y = ex 1 ey ex ey • For r = m ∈ N, emx = e z }m { x···x = z }m { ex ···ex = (ex)m • For r = 1 n, n ∈ N and n 6= 0, ex = e n n x = e 1 nx n ⇒ e n x = (ex) 1 • For r rational, let r = m n, m, n ∈ NMy own overlyfanciful suggestion is to take the onreading of Ui's name kanji (憂, 'yuu', "grief"), add it with the radical for 'person' (as the "I") which will become 優, the kanji for "gentleness", Ui's character in whole (This is ultimately why Ui was given that "depressing" kanji as her name in the first place, she "warms up to people Word Achivos En Caja Ikus solutions

Review for Midterm 2, Concepts Let f be continuous on a , b Definitions Let f be a function with domain D f has an absolute maximum on D at x=c if f(x)≤f(c)forallxinD f has an absolute minimum on D at x=c if f(x)≥f(c)forallxinD f has a relative maximum at x=c if there exist an interval (r,s) containing c such thatf(x)≤f(c)forallxinbothDand(r,s)H a , L b M a G R B S a , Occ a a Sa a H a A a5 (a) Determine the Taylor polynomial Pn(x) of degree n centered at 0 for the function ex (b) Give an expression for the remainder Rn(x) in Taylor's theorem such that ex = P n(x)Rn(x) (c) Prove that ex ≥ 1x for all x ∈ R, with equality if and only if x = 0 (d) Prove that eˇ > Solved For Each Of The Following Distributions Find K Such Chegg Com ‰Âˆ¤‚¢ ƒXƒk[ƒs[ –ì‹… ƒCƒ‰ƒXƒg

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